Calculate the molarity of 2.00 l of solution that contains 200.0 g of naoh. What volume of 12.0 m hcl is required to prepare 16.0 l of 0.250 m hydrochloric acid? Web solution for what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl? Ml 0.560 ml 21.9 ml 257 ml this problem has been solved! Mass of hcl in one molar solution which is the molar mass is 36.5. The density of your hcl is 1.179. Web since you need $\pu{262.5 mmol}$, and the $\pu{12 m }$ solution has $\pu{12 mmol}$ per $\pu{ml}$, then you need $\pu{262.5mmol}\div \pu{12m} = \pu{21.875 ml}$ of $\pu{12 m. Web 75ml=0.075lmolarity=moles/litersmoles=0.075(3.50)=0.2625since the number of moles never changes,we know there are 0.2625moles (or 0.26) in the 12m. Given, initial molarity of hcl , m1 = 12.0 m final molarity of hcl ,m2 = 3.50 m final volume of hcl… q: None of the above answered:.
Given, initial molarity of hcl , m1 = 12.0 m final molarity of hcl ,m2 = 3.50 m final volume of hcl… q: Web what volume of 12.0 m hcl is needed to contain 3.00 moles of hcl? 12 m = 12 moles hcl per 1 liter of solution.so 12 moles/ 1 liter = 3 moles/ x liters. = molarity of hcl solution =. Calculate the molarity of 2.00 l of solution that contains 200.0 g of naoh. Web solution for what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl? What volume of 12.0 m hcl is required to prepare 16.0 l of 0.250 m hydrochloric acid? You'll get a detailed solution from a. X = 0.25 liters of 250ml. Web 75ml=0.075lmolarity=moles/litersmoles=0.075(3.50)=0.2625since the number of moles never changes,we know there are 0.2625moles (or 0.26) in the 12m. Web since you need $\pu{262.5 mmol}$, and the $\pu{12 m }$ solution has $\pu{12 mmol}$ per $\pu{ml}$, then you need $\pu{262.5mmol}\div \pu{12m} = \pu{21.875 ml}$ of $\pu{12 m.
